Hello,

I have two different windows.

Window1 widget ids

#define GUI_ID_WINDOW_0 (GUI_ID_USER + 0x00)
#define GUI_ID_ICONVIEW0 (GUI_ID_USER + 0x01)

#define GUI_ID_ICONVIEW1 (GUI_ID_USER + 0x02)
...

Window2 widget ids

#define GUI_ID_WINDOW_0 (GUI_ID_USER + 0x00)
#define GUI_ID_ICONVIEW0 (GUI_ID_USER + 0x01)
#define GUI_ID_ICONVIEW1 (GUI_ID_USER + 0x02)
...

each window has a resource table which is used to create the widgets by using GUI_CreateDialogBox()
My question is can two windows have same widget id's?

On Window1 widget iconview1 released event i have deleted the current window by using WM_DeleteWindow()
and created the window2 using GUI_CreateDialogBox()

I get the following emwin error.




When i modify the GUI ID's as below the error does not come.
I have kept different ids for iconview widget in both windows.

Window1 widget ids

#define GUI_ID_WINDOW_0 (GUI_ID_USER + 0x00)
#define GUI_ID_ICONVIEW0 (GUI_ID_USER + 0x01)
#define GUI_ID_ICONVIEW1 (GUI_ID_USER + 0x02)
...

Window2 widget ids

#define GUI_ID_WINDOW_0 (GUI_ID_USER + 0x00)
#define GUI_ID_ICONVIEW0 (GUI_ID_USER + 0x03)
#define GUI_ID_ICONVIEW1 (GUI_ID_USER + 0x04)

So if GUI id's for Iconview widget are same i get the error as above and if GUI id's are different i don't get any error.

I get this error for iconview widgets only.

My question is why the error is coming?
What is the standard way of defining id's if 2 windows are used, each window with 2 iconview widgets?

Thanks

Regards,

Anuj